Maths Help - Pythagoras?

Science & Mathematics by Anonymous 2018-07-12 07:34:52

Social Science

7 answers

A contractor wishes to reach the top of a building 10m high with a ladder. If the ladder must be 3.3m away from the foot of the building, how long must the ladder be?

Anonymous

ladder = √(10²+3.3²) ≅ 10.53 m
Anonymous

A contractor wishes to reach the top of a building 10 m high with a ladder. If the ladder must be 3.3 m away from the foot of the building, how long must the ladder be? l^2 = 100 + 10.89 l = sqrt 110.89 = 10.53 m
Anonymous

Let x be the ladder length. 3.3^2 + 10^2 = x^2 10.89 + 100 = x^2 x^2 = 110.89 x = 10.53m
Anonymous

√110.89 = 10.53 m
Anonymous

Using Pythagoras' theorem length of ladder to two decimal places is 10.53m
Anonymous

x² = 3•3² + 10² x² = 110•89 x = 10•53 ft______length of ladder
Anonymous

draw a diagram - it's worth marks length of ladder is sq root of sum of building height squared and distance at base squared = sq rt of (100 + 10.89) = 10.53m