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Science & Mathematics by Anonymous 2018-07-13 03:34:54
Social Science
Two cards are drawn from standard deck. w/ replacement. What is the prob that the 1st card is King and the 2nd is not King? P(K1 and not K2)?
3 answers
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Anonymous
1/13,12/13
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Anonymous
With replacement, for both draws there are 4 kings and 52 cards: P(K1 and !K2) = (4/52)(48/52) = 192/2704 = 12/169 ≈ 7.10%
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Anonymous
P(K)=4/52=1/13 P(not K)= 48/52=12/13 P(K1 not K2)= 12/13^2=12/169=.071