Anonymous

P(2 selections are blue)= 10C2/15C2)= [10!/(8!2!)][13!2!/15!]=3/7

Anonymous

It depends on whether you replace the first ball or not. Replace the first.... 10/15 x10/15 = 100/225 = 20/45 = 4/9 Not replace the first...10/15 x 9/14 = 90/210 = 3/7

Anonymous

It depends on how cold it is outside and whether the guys are wearing boxers or jockeys.

Anonymous

first is 10/15 assuming you don't return the first second is 9/14 for both it is (10/15)(9/14) (2/3)(9/14) (2)(3/14) 6/14 or 0.429

Anonymous

Without replacement: (10/15) * (9/14) => (2/3) * (9/14) => (2/14) * (9/3) => (1/7) * 3 => 3/7 With replacement: (10/15) * (10/15) => (2/3) * (2/3) => 4/9

Anonymous

(10/15)(9/14) = 90/210 = 3/7