If the product of twice a number decreased by five and five times a number increased by seven is zero; find the numbers?

Science & Mathematics by Anonymous 2018-07-16 20:03:57

Social Science

6 answers

Anonymous

(2x - 5)(5y + 7) = 0 The numbers are 2.5 and -1.4
Anonymous

(2a-5)(5b+7) = 0 Per the Zero Product Rule: 2a-5 = 0 → a = 5/2 5b+7 = 0 → b = -7/5 Ans: -7/5 and 5/2
Anonymous

(2x - 5)(5x + 7) = 0 x = 5/2 or x = -7/5
Anonymous

(2n-5)×(5n+7) = 0 n = 2.5, -1.4
Anonymous

(2x-5)(5x+7) =0 x = 5/2 ; -7/5
Anonymous

(2a - 5)(5b - 7) = 0 2a - 5 = 0 or 5b - 7 = 0 2a = 5 or 5b = 7 a = 5/2 or b = 7/5 a = 2.5 or b = 1.4