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The width of a rectangle is 13 feet less than twice it’s length. If the area of the rectangle is 68 square feet, find its length and width.?

Science & Mathematics by Anonymous 2018-07-17 16:34:59

Social Science

The width of a rectangle is 13 feet less than twice it’s length. If the area of the rectangle is 68 square feet, find its length and width.?

3 answers

  • Anonymous

    l(2l - 13) = 68 2l^2 - 13l - 68 = 0 l ≈ 9.9255 feet , w ≈ 6.851 feet.

  • Anonymous

    The width of a rectangle is 13 feet less than twice it’s length. If the area of the rectangle is 68 square feet, find its length and width. l(2l - 13) = 68 2l^2 - 13l - 68 = 0 l ≈ 9.9255 feet , w ≈ 6.851 feet.

  • Anonymous

    (2l-13)*l=68 2l^2-13l-68=0

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