Hi can someone tell me how to factorise 5x(2x-5)^2

Science & Mathematics by Anonymous 2018-07-18 07:34:26

Social Science

Hi can someone tell me how to factorise 5x(2x-5)^2 - (2x-5)^3?

8 answers

Anonymous

5x(2x - 5)^2 - (2x - 5)^3 = (5x - (2x - 5))(2x - 5)^2 = (3x + 5)(2x - 5)^2
Anonymous

[ 2x - 5 ]^2 [ 5x - (2x - 5) ] [ 2x - 5 ]^2 [ 3x + 5 ]
Anonymous

5x(2x - 5)² - (2x - 5)³ (2x - 5) is common to both terms (twice), so we can factor out (2x - 5)² to leave: (2x - 5)² [5x - (2x - 5)] Now we can simplify what's left: (2x - 5)² (5x - 2x + 5) (2x - 5)² (3x + 5)
Anonymous

5x(2x-5)² - (2x-5)³ =(2x-5)²{5x - (2x-5)} =(2x-5)²{5x - 2x+5} =(2x-5)²{3x+5}
Anonymous

5x(2x - 5)^2 - (2x - 5)^3 = (2x - 5)^2(3x + 5)
Anonymous

(2x-5)^2*(5x- (2x-5)) can you take it further?
Anonymous

[2x-5]^2[5x-(2x-5)] = (3x+5)(2x-5)^2
Anonymous

= 5x.(2x - 5)² - (2x - 5)³ = 5x.(2x - 5)² - (2x - 5)².(2x - 5) → you can factorize: (2x - 5)² = (2x - 5)².[5x - (2x - 5)] = (2x - 5)².[5x - 2x + 5] = (2x - 5)².(3x + 5)