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3m^2+2m+7=0 complete the square?

Science & Mathematics by Anonymous 2018-07-18 02:05:13

Social Science

3m^2+2m+7=0 complete the square?

4 answers

Solve the quadratic equation by completing the square.

  • Anonymous

    3m^2 + 2m + 7 = 0 3 (m + 1/3)^2 + 20/3 = 0

  • Anonymous

    3m^2+2m+7=0 m^2 + (2/3)m = -(7/3) m^2 + (2/3)m + (1/3)^2 = (1/3)^2 - (7/3) you can continue

  • Anonymous

    3m² + 2m + 7 = 0 {then multiply through by 4a=12} 36m² + 24m + 84 = 0 (6m)² + 2*2*6m + 2² + 80 = 0 (6m + 2)² - (4√5 i)² = 0 {difference of two completed squares} (6m + 2 ± 4√5 i) = 0 6m = -2 ± 4√5 i m = -⅓ ± ⅔√5 i

  • Anonymous

    c = (b^2)/(4a) 3m^2 + 2m = -7 9m^2 + 6m = -21 9m^2 + 6m + 1 = -21 + 1 (3m + 1)^2 = -20 3m + 1 = +/- sqrt(-20) 3m = -1 +/- sqrt(-20) m = (-1 +/- sqrt(-20)) / 3 m =~ -0.33333333333333333333333333333333 +/- 1.4907119849998597976061157791542i

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