Anonymous

The circle with a radius the length of a semi-major axis and centred at an end of the minor axis passes through the major axis at the foci. Graph (including answer(s)): https://www.desmos.com/calculator/wog0nh...

Anonymous

x²/36 + y²/11 = 1 36>11, so the ellipse is horizontal. General equation for a horizontal ellipse:  (x-h)²/a² + (y-k)²/b² = 1 with  a² ≥ b²  center (h,k)  linear eccentricity c = √(a²-b²)  foci (h±c,k) Apply your data and solve for h, k, a, and b. h = 0 k = 0 a = 6 b = √11 c = √(a²-b²) = √(36-11) = 5 foci (h±c,k) = (0±5,0) = (5,0) and (-5,0)