Anonymous

c-b = 3 and b-a = 3, so c-a = 6 GCF(3,6)=3, so u = (c-a)/3 = 2 and v = (c-b)/3 = 1 From shortest to longest, the lengths of the sides (in inches) are: 3(√(2×1×2) + 1) = 9 3(√(2×1×2) + 2) = 12 3(√(2×1×2) + 1 + 2) = 15

Anonymous

Let the hypotenuse be c; the longer leg be b & the shorter leg be a, then a=b-3, c=b+3. Thus (b+3)^2=b^2+(b-3)^2 => b^2-6b=6b => b(b-12)=0 => b=12 in since b=/=0 => a=12-3=9 in c=12+3=15 in