Using the discriminate, determine the number and type of solutions for this equation. 4x^2-4x+1=0?

Science & Mathematics by Anonymous 2018-05-11 13:11:05

Social Science

4 answers

Anonymous

d = (-4)^2 - 4(4)(1) d = 0 one real solution
Anonymous

The "b^2 - 4ac" is 16-16 = 0, so there are two real, equal roots ... in other words, only one distinct solution, viz. x = 1/2.
Anonymous

b² - 4ac = (-4)² - 4(4)(1) = 16 - 16 = 0 Quadratic is a perfect square whose solution set contains one real value with multiplicity 2.
Anonymous

discriminant = (-4)² - 4(4)(1) = 0 1 real solution