Can somebody please answer the following physics question?

Science & Mathematics by Anonymous 2018-06-03 13:34:54

Social Science

3 answers

An object with initial velocity 3.9 m/s moves along a line with constant acceleration and travels 800 m in 40 sec. What is the acceleration in m/s2? ROUND TO FOUR DECIMAL PLACES!!!!

Anonymous

x = Vo*t+a/2*t^2 (800-3.9*40)*2 = a*t^2 a = (800-3.9*40)*2/1600 = 0.8050 m/sec^2
Anonymous

Use the following equation. d = vi * t + ½ * a * t^2 800 = 3.9 * 40 + ½ * a * 40^2 20 * a = 644 a = 32.2 m/s^2
Anonymous

x = ut + (1/2)at^2 , a=acceleration , u = initial velocity , x = distance , t=time