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Science & Mathematics by Anonymous 2018-06-06 14:03:10
Social Science
A 75 W lightbulb is being run on a 110 V outlet. Determine the resistance of the lightbulb. Provide a detailed description of the process.?
4 answers
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Anonymous
R= E^2/P = 110^2 = 161.333 Ω The switch is turned on and a current of 682 mA. flows through the lamp filament causing it to radiate energy Incandescently without consumption.
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Anonymous
Operating resistance of bulb equals relatively close to (110V^2)/(75W) = [(12,100)/(75)]Ohms when operated under the same conditions that this type bulb was rated at by it's manufacturer.
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Anonymous
R = 75 / 110^2 ohm
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Anonymous
First find the current....power/voltage = 75/110 = 0.682 amp Resistance = voltage/ current = 110/0.682 = 161.3 ohms.