Anonymous

rule The area of a trapezoid A =(a+b) * h / 2

Anonymous

Area of a trapezoidal = (1/2)x(sum of parallel sides)xheight Here one base = 6 mm Let other base =b Height, h= 12 mm Area= 150 sq. mm Hence 150=(1/2)(6+b)x12 or 6+b= 150/6=25 mm I.e. b= 19 mm

Anonymous

150 = (b + 6)12/2 150 = (b + 6)6 25 = b + 6 b = 19mm

Anonymous

150 = 6(x+6) x = 19 mm

Anonymous

Area of a trapezoid is found with the formula, A = [(a + b) / 2] x h. 150 = [(a + 6) / 2] x 12 25 = a + 6 a = 19 mm

Anonymous

The area of a trapezoid is the average of the bases, times the height. A = ½(b₁ + b₂) * h You know: A = 150 b₁ = 6 h = 12 So: 150 = ½(6 + b₂) * 12 150 = 6(6 + b₂) 25 = 6 + b₂ b₂ = 25 - 6 b₂ = 19 Answer: 19 mm