Anonymous

The original expression =[(45yx^2)^(1/3)][(6xy^3)^(1/2)] =[3^(2/3+1/2)][5^(1/3)]2^(1/2) [x^(2/3+1/2)]y^(1/3+3/2) =[3^(7/6)][5^(1/3)][2^(1/2)*x^(7/6)] y^(11/6) =3[3^(1/6)][5^(1/3)][2^(1/2)]x[x^(1/6)] y[ y^(5/6)] =3[5^(1/3)][2^(1/2)][3(x^7)(y^11)]^(1/6...