Anonymous

Volume of the square pyramid, V= 60 cubic meters Height of the pyramid , h=2 meters. Let length of the side =L Then V=(1/3)L²h i.e. 60 =(1/3)L²x2 i.e. L² =(60x3)/2=90 and L=√90 =3√10 m

Anonymous

base length b = √(3V/h) = √(3·60/2) = 3√10 = 9.49 m

Anonymous

Answer is 9.486 metres.

Anonymous

Volume = (1/3) B h B = area of the base which is a square 60 = (1/3) B (2) 60 = (2/3) B B = (60)(3/2) B = 90 Area of the base = side^2 side^2 = 90 side = sqrt(90) = sqrt(9)sqrt(10) = 3 sqrt(10) m (side length)