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Science & Mathematics by Anonymous 2018-05-25 19:37:08
Social Science
What is the domain of f(x)= (x-9)^1/2?
6 answers
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Anonymous
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Anonymous
x-9 >= 0 in order for square root (power 1/2) to be real. x >= 9 domain [9,infinity)
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Anonymous
x >= 9, as (x - 9)^(1/2) is the same as sqrt(x - 9). You can't take the square root of a negative real number and get a real number.
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Anonymous
[9, ∞)
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Anonymous
9 <= x
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Anonymous
x E R : x >= 9