Please help with this math problem?

Science & Mathematics by Anonymous 2018-05-18 21:08:35

Social Science

7 answers

The length of a rectangle is three times its width. If the perimeter of the rectangle is 48 ft, find its length and width.

Anonymous

P = 2l + 2w 48 = 2(3x) + 2x You finish.
Anonymous

L = 3w 2L + 2w = 48 Solve the system of equations. 2(3w) + 2w = 48 8w = 48 w = 6ft L = 18ft
Anonymous

The length of a rectangle is three times its width. The perimeter of the rectangle is 48 ft, Hence, its length is 18 ft and width.is 6 ft.
Anonymous

L = 3W perimeter = 2L + 2W = 48 2(3W) + 2W = 48 8W = 48 W = 6 ft L = 3W = 18 ft
Anonymous

L = 3W Perimeter = 2L+2W 2L+2W = 48 2(3W) + 2W = 48 6W+2W =48 8W=48 W= 6 ft L= 3W= 3*6 = 18 ft
Anonymous

Call l,w the two lengths of rectangle From data l=3w perimeter =2(l+w)=48 ft ⇒ l+w=24 ft Plug l=3w into the last equation 3w+w=24 4w=24 w=6 ft l=3*w=18 ft
Anonymous

L=3W p=2L + 2W= 6W + 2W= 8W= 48 W= 6ft, L= 18 ft