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A diameter of a circle has endpoints P(-10,-2) and Q(4,6). Find the radio. If answer is not an integer, express it in radical form
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Anonymous
A diameter of a circle with endpoints at P(-10,-2) and Q(4,6) = 2 sqrt(65) ≈ 16.1245 Radius = sqrt(65) ≈ 8.06225
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Anonymous
Use Pythagoras d^2 = (-10 - 4)^2 + ( -2 - 6)^2 d^2 = (-14)^2 + (-8)^2 d^2 = 196 + 64 d^2 = 260 d = sqrt(260) d = sqrt(2 x 2 x 5 x 13) d = 2sqrt(65) = 16.1245155....
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Anonymous
Ans. 2sqr(65)