The under stretched spring has a length of 0.20 m and spring constant 1500 N/m.?

Science & Mathematics by Anonymous 2018-05-25 11:03:17

Social Science

5 answers

The under stretched spring has a length of 0.20 m and spring constant 1500 N/m. A weight is hung from the spring, causing it to stretch to a length of 0.60 m. How many joules of elastic potential energy are stored in this stretched spring?

Anonymous

I have no idea
Anonymous

U=1/2Kx^2 U=1/2(1500)(0.2)^2 U=30 J
Anonymous

stored energy E = k/2*(0.6-0.2)^2 = 750*0.16 = 120.0 joule
Anonymous

PE stored = kx^2/2, where k = elastic constant and x = extension = (1500)(0.6 - 0.2)^2/2 = (1500)(0.4)^2/2 = 120 J
Anonymous

Corn