How to solve log 3 2c=-2?

Science & Mathematics by Anonymous 2018-05-25 21:35:21

Social Science

6 answers

Anonymous

2c = 1/9 c = 1/18
Anonymous

log₃(2c) = -2 2c = 3⁻² = 1/9 c = 1/18
Anonymous

rule log(base a) of x = y <---> x = a^y
Anonymous

log (base 3) 2c = -2 3^(-2) = 2c 2c = 1/9 c = 1/18 Rule: log (base b) a = c <=> a = b^c
Anonymous

Do you mean log(base 3) of (2c) = -2 ? Then 3^(-2) = 2c. So then 1/9 = 2c, and c = 1/18.
Anonymous

already answered