Anonymous

V₁=4.2L T₁=38°C = 38+273.15 K =311.15 K V₂=? T₂=115°C = 115 + 273.15 = 388.15 K Assuming that the balloon expands enough to keep the pressure constant. V₁/T₁ = V₂/T₂ V₂ = V₁T₂/T₁ = 4.2*388.15/311.15 = 5.24 L

Anonymous

It seems rather simple if you know the proper equation. Which, I don't but you should.

Anonymous

Yes

Anonymous

V1/T1 = V2/T2 Convert temperatures to Kelvin, plug in and solve for V2. 4.2 L / 311 K = V2 / 388 V2 = 5.2 L