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Science & Mathematics by Anonymous 2018-06-01 11:03:26
Social Science
Need help with a question: A 2850 Kg boulder is 357 m above the ground. As it falls and hits the floor, how much kinetic energy does it have?
2 answers
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Anonymous
Air friction is not considered, then potential energy Ep = m*g*h is conserved and it is equal to the kinetic energy Ek = m/2*V^2 at the moment of the impact !!!! Ek = m*g*h = 2850*357*9.806*10^-6 = 10.0 Mjoule
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Anonymous
Same as the PE it had when it was 357 m above the ground.