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Integral cos2xcos6x dx?

Science & Mathematics by Anonymous 2018-05-12 02:39:48

Social Science

Integral cos2xcos6x dx?

4 answers

  • Anonymous

    Rule cos(a) cos(b) = [cos(a - b) + cos(a + b)]/2

  • Anonymous

                                         

  • Anonymous

    ∫ cos(2x) cos(6x) dx => use cos(a) cos(b) = 1/2[cos(a - b) + cos(a + b)]: let a = 6x, b=2x: = 1/2 ∫ cos(4x) dx + 1/2 ∫ cos(8x) dx = 1/8 sin(4x) + 1/16 sin(8x)

  • Anonymous

    Can you upload a picture of the problem?

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