The base of an isoscles triangle is 21 centimeters long. The altitude to the base is 9 cm long. What's the approx. base angle?

Science & Mathematics by Anonymous 2018-06-09 01:33:24

Social Science

8 answers

Anonymous

The altitude divides the triangle into 2 identical right triangles. Consider one of them, we get tan(base <)=9/(21/2) => base <=tan^-1(9/10.5) => base <=40.6* approximately.
Anonymous

tan Ө = 9 / 10•5 = 18 / 21 Ө = 41 ⁰
Anonymous

Tan (angle) = 9/(21/2) => Tan(angle) = 18/21 = 6/7 Angle = Tan^-1(6/7) = Tan^-1(0.85714...) Angle = 40.6... degrees.
Anonymous

The isosceles triangle will consist of 2 right angle triangles with height of 9 cm and a base of 10.5 cm and by using the tangent ratio of 9/10.5 its base angles are 40.6 approx.
Anonymous

The base angle is given by: tanΘ = 9/(21/2) = 18/21 = 6/7 Θ = arctan(6/7) ≈ 40.601°
Anonymous

θ = arctan(9/10.5) = 40.6°
Anonymous

tan x = 9/10;5 arc tan 3/3.5 Base angle: 40.6°
Anonymous

arctan ( 9 / 11.5 ).............{0.664....38° }