Anonymous

Call the small one x and the larger one y x + y = 74 But y = (2x + 26) Substitute into first equation: x + (2x + 26) = 74 3x + 26 = 74 3x = 48 x = 16 if x = 16 y = (16 x 2) + 26 = 58 Ans 16 + 58 = 74

Anonymous

a+2a+26 = 74 a = 16 b = 58

Anonymous

Let n = smaller number. Then 2n + 26 = larger number Therefore n + 2n + 26 = 74 3n = 48 n = 16, smaller number 2(16) + 26 = 58 .........larger number

Anonymous

Let the integers be m & n m = 2n + 26 m + n = 74 Substituting 2n + 26 + n = 74 3n = 74 - 26 3n = 48 n = 16 Hence m = 2(16) + 26 = 32 + 26 = 58 58 + 16 = 74

Anonymous

Here's all the steps: x + y = 74 y = (x + 26) so x + y = 74 becomes x + y = 74 x + (x + 26) = 74 2x +26 = 74 2x = 74 - 26 2x = 48 x= 24 y = x + 26 y = 24+26 y= 50 So x= 24, y=50 ===

Anonymous

m+n = 74 n = m-26 m+(m-26) = 74 m = 50 n = 24

Anonymous

Turn words into equations is the question A+B=74 A=26+2B Substitute 26+2B+B=74 3B=48 B=16 A=26+2B A=26+32=58 58 and 16 58+16=74 checks 58 minus 26 = 32 and 32 is 2x 16 checks

Anonymous

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Anonymous

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Anonymous

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