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(w-7)^2=2w^2-17w+39?

Science & Mathematics by Anonymous 2018-06-10 15:32:38

Social Science

(w-7)^2=2w^2-17w+39?

8 answers

  • Anonymous

    (w - 7)^2 = 2w^2 - 17w + 39 w^2 - 3w - 10 = 0 (w - 5)(w + 2) = 0 Solutions: w = -2 w = 5

  • Anonymous

    (w - 7)^2 = 2w^2 - 17w + 39 w^2 - 3x - 10 = 0 (w - 5)(w + 2) = 0 Solutions: w = -2 w = 5

  • Anonymous

    (w - 7)^2 = 2w^2 - 17w + 39 w^2 - 14w + 49 = 2w^2 - 17w + 39 0 = w^2 - 3w - 10 0 = (w - 5)(w + 2) w = 5 or w = -2

  • Anonymous

    w² - 14w + 49 = 2w² - 17w + 39 w² - 3w - 10 = 0 [ w - 5 ] [ w + 2 ] = 0 w = 5 , w = - 2

  • Anonymous

    (w - 7)^2 = 2w^2 - 17w + 39 w^2 - 14w + 49 = 2w^2 - 17w + 39 0 = w^2 - 3w - 10 0 = (w + 2)(w - 5) ---> w = -2 or 5.

  • Anonymous

    Look it up on google, dumbass

  • Anonymous

    Solution: w = {5, -2}

  • Anonymous

    w^2 - 14w + 49 = 2w^2 - 17w + 39 0 = w^2 - 3w - 10 You can solve that by factoring or by using the quadratic formula. 0 = (w + 2)(w - 5) or w = [+3 +- sqrt(3^2 - 4*1*(-10)) ] / 2 = [3 +- sqrt(49) ] / 2

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