Anonymous

(2x^5 + 5x^3 + 3x^2 - 7x - 9) / (x^2 - 3) Quotient and remainder: 2 x^5 + 5 x^3 + 3 x^2 - 7 x - 9 = (2 x^3 + 11 x + 3) × (x^2 - 3) + 26 x

Anonymous

(2x^5+5x^3+3x^2-7x-9) = 2x⁵−6x³ +11x³−33x +3x² −9 +26x = 2x³ (x²−3) +11x(x²−3)+3(x²−3) +26x = (x²−3){2x³ +11x+3] +26x Hence (2x^5+5x^3+3x^2-7x-9) ÷ (x²−3) =[(x²−3){2x³ +11x+3} +26x] ÷ (x²−3) Quotient 2x³ +11x+3 Remainder 26x