Anonymous

Factor by using completing the square. Divide across by -1. x^2 - 6x + 4 = 0 x^2 - 6x = - 4 (1/2)6 = 3^2 = 9 Add 9 to both sides. x^2 - 6x + 9 = - 4 + 9 (x - 3)(x - 3) = 5 (x - 3)^2 = 5 f(x) = (x - 3)^2 - 5

Anonymous

-x^2+6x-4 = -(x^2-6x+4) = - ( x^2-6x+9 -9 +4) = - ( (x^2-6x+9) -5 ) = - ( (x-3)^2 - 5) = - (x-3)^2+ 5

Anonymous

It is in standard form. Did you mean vertex form? If so, f(x) = -x^2 + 6x - 4 f(x) = -(x^2 - 6x) - 4 f(x) = -(x^2 - 6x + (6/2)^2) - 4 + (6/2)^2 f(x) = -(x - 3)^2 + 5

Anonymous

f(x)=-x^2+6x-4 is in standard form

Anonymous

It is already in standard form. standard form is generally defined as y = ax^2 + bx + c Your other answer converted to vertex format so you can read the vertex out of the equation. y = a(x-h)^2 + k will have vertex (h,k)

Anonymous

Factor ... by completing the square f(x)=-x^2+6x-4 f(x)= - (x^2 - 6x+ 9) -4+ 9 f(x) = -(x- 3)^2 + 5