A case of grapefruit weighs 35 3/4 pounds. Of this weight, 1/8 is not ripe. What is the weight of the grapefruit that are ripe?

Science & Mathematics by Anonymous 2018-06-11 21:03:16

Social Science

12 answers

Anonymous

Ans. (35+3/4)*(1-1/8)=(143/4)(7/8)=31.28125 lb.
Anonymous

1/8 of 143/4 pounds = 143/32 pounds or 4 15/32 pounds then 35 24/32 pounds - 4 15/32 pounds = 31 9/32 pounds.
Anonymous

(1/8) not ripe so (7/8) are ripe. Lbs of the ripe = (7/8)[35+(3/4)] = (7/8)[32+(15/4)] = 28+(105/32) = 31 9/32.
Anonymous

if 1/8 is not ripe, 7/8 is ripe 7/8 x 35 3/4 = 7/8 x 143/4 = 1001/32 = 31 9/32 pounds
Anonymous

7/8 x 143/4 = 31•3 lbs are ripe
Anonymous

35 3/4 - 1/8 = 35 6/8 - 1/8 = 35 5/8
Anonymous

7/8 * 143/4 = 1001/32 lb = 31 9/32 lb
Anonymous

31.28125 pounds
Anonymous

divide the total weight by 8, that is the unripe portion, then subtract that from the full weight and that is the ripe portion
Anonymous

1 - 1/8 = 7/8 7/8 * 35 3/4 = 7/8 * (35*4 + 3)/4 = 1001/32 = 31 9/32 pounds
Anonymous

Fraction of ripe = 7/8 Weight of grapefruit ripe = 7/8 of 35 3/4 = 7/8 x 143/4 = (7 x 143)/32 = 1001/32 31 9/32
Anonymous

(7/8) of 35 3/4 = (7/8)x(143/4) = (7 x 143}/(8x4) = ...