A line passing through (4,-3) and perpendicular with y-2x=8?

Science & Mathematics by Anonymous 2018-06-11 21:31:37

Social Science

6 answers

A line passing through (4,-3) and perpendicular to the line with equation y-2x=8. Write your answer in slope-intercept form.

Anonymous

y-2x=8=>y=2x+8 having the slope=2. A line which is perpendicular to this line should have the slope=-1/2. Thus the required equation of the line is y-(-3)=(-1/2)(x-4) => y+3=-x/2+2 => y=-x/2-1
Anonymous

y - 2x = 8 y = 2x + 8, which has a slope of 2. Therefore, the perpendicular line has a slope of -1/2. The perpendicular is y - (-3) = -1/2(x - 4) y + 3 = -x/2 + 2 y = -x/2 - 1
Anonymous

y+3 = (-1/2)(x-4) y+3 = 2 - x/2 y = -x/2 - 1
Anonymous

y = 2x + 8 m1 = 2 m2 = - 1/2 y + 3 = (-1/2) ( x - 4 ) y = (-1/2) x + 2 - 3 y = (-1/2) x - 1
Anonymous

I DON'T CARE ASSHOLE. NOW FUCΚ OFF.
Anonymous

line perpendicular with y-2x=8 is 2y+x = c , point (4,-3) --->c= ...