Anonymous

(x^2-8x+7)/(x^2-2x+7)<0 => (x-1)(x-7)/[(x-1)^2+6]<0 => (x-1)(x-7)<0 => 1<x<7

Anonymous

Factorising the expressions, (x-1)(x-7)/(x^2-2x+1+6) < 0 (x-1)(x-7)/[(x-1)^2+6] < 0 The denominator is positive for all real values of x. Therefore, (x-1)(x-7) < 0 1 < x < 7