Anonymous

Let h be the length of the altitude, then h=sqr[11^2-(11/2)^2] (Pythagoras' theorem) => h=11sqr(3)/2 units. or h=9.53 units approximately.

Anonymous

Equilateral triangle has 3 equal sides of length s = 11 units. Length of altitude = [s^2 - (s/2)^2]^(1/2) = s[1 - (1/4)]^(1/2) = (srt3)/2 = (11rt3)/2 units.

Anonymous

Each angle is 60 degrees. sin 60 = Altitude/length of side (from Pythagoras) A = 9.526 inches Or, from Pythagoras theorem 5.5 squared + Altitude squared = 11 squared Altitude squared = 11^2 - 5.5^2 = (16.5)(5.5) = 90.75 Altitude = 9.526 inches

Anonymous

Set it up like a pyramid. Divide the bottom in half with a vertical line to the point at the top. Now you have two right sided pyramids with a base of 5.5 and a hypotenus of 11. Now you have the means to find the height, use Pathagoras.

Anonymous

You can use the Pythagorean