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Science & Mathematics by Anonymous 2018-06-13 00:01:48
Social Science
What is the product of the polynomials (4x^3+8x)(x^2-1) A. 4x^5+8x^2-8x B.4x^5+4x^3+32 C.4x^5-4x^3+8x^2-8x D.4x^5+4x^3-8x?
10 answers
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Anonymous
(4x^3 + 8x)(x^2 - 1) = 4x^5 + 8x^3 - 4x^3 - 8x = 4x^5 + 4x^3 - 8x Choice D. is correct.
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Anonymous
Ans. (4x^3+8x)(x^2-1) =4x^5-4x^3+8x^3-8x =4x^5+4x^3-8x =D
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Anonymous
D x=1 and -1
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Anonymous
= (4x³ + 8x).(x² - 1) = 4x⁵ - 4x³ + 8x³ - 8x = 4x⁵ + 4x³ - 8x ← D answer
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Anonymous
(4x^3 + 8x)((x^2 - 1) = 4x(x^2 +2)(x^2 - 1) = 4x(x^4 + x^2 - 2) = 4x^5 +4x^3 - 8x. Choice D. pertains.
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Anonymous
(4x^3 + 8x)(x^2 - 1) = 4x^5 - 4x^3 + 8x^3 - 8x = 4x^5 + 4x^3 - 8x Answer choice: D. 4x^5 + 4x^3 - 8x
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Anonymous
D). Just utilize the FOIL method.
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Anonymous
Use FOIL method: F = (4x^3)(x^2)=4x^5; O = (4x^3)(-1)=-4x^3; I = (8x)(x^2)=8x^3; L=(8x)(-1)=-8x. Notice that the O and I are like terms; combining gives 4x^3. So correct answer is choice D
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Anonymous
Can't be A or C -- x^2 will not be in the result Can't be B -- there will be no x^0 terms So D
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Anonymous
obviously D)
