QUICK HELP ME!!! expand and simplify (2+sqrt3) (1/sqrt3) give your answer in the form a+b sqrt3. where a and b are integers!!?

Science & Mathematics by Anonymous 2018-06-15 09:33:43

Social Science

8 answers

Anonymous

(2 + sqrt3) (1/sqrt3) = 2/sqrt3 + 1
Anonymous

(2 + sqrt(3))*(1/sqrt(3)) = 2/sqrt(3) + 1 = 2*sqrt(3)/3 + 1. If you wrote the original expression correctly, a and b CANNOT both be integers, they would be a = 1 and b = (2/3).
Anonymous

2/√3 + 1 = 1 + [2√3]/3
Anonymous

(2+sqr(3))(1/sqr(3)) = 2/sqr(3)+1 = 1+2sqr(3)/3 => a=1 b=2/3 Check your problem.
Anonymous

Just key in the information on a scientific calculator which will give 1 + 2/3 the square root of 3
Anonymous

(2 + √3) (1/√3) = 2/√3 + √3/√3 = 1 + 2/√3 = 1 + 2/3 √3 a = 1 and b = 2/3 (not an integer, but I'm not seeing a way around that)
Anonymous

. (2 + √3) (1/√3) = [ (2 + √3)/√3 ] (√3 / √3 ) = 1 + ⅔√3 b won’t be an integer unless the form was a + b/√3 then you would end up with 1 + ⅔√3 = 1 + 2/√3
Anonymous

1 + 2/sqrt3 = 1+(2/3)sqrt3