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Given that f(x)=x^2-4 and g(x)=2x+16, find (g-f)(-9) if it exists?

Science & Mathematics by Anonymous 2018-06-15 16:32:59

Social Science

Given that f(x)=x^2-4 and g(x)=2x+16, find (g-f)(-9) if it exists?

4 answers

  • Anonymous

    f(x) = x^2 - 4 g(x) = 2x + 16 (g - f)(-9) = -79

  • Anonymous

    (g - f)(-9) = 2(-9) + 16 - ((-9)^2 - 4) = -18 + 16 - (81 - 4) = -79. Final.

  • Anonymous

    2x + 16 - (x^2) + 4 = -(x^2) + 2x + 20; When x = -9; -((-9)^2) + 2*-9 + 20 = -81 - 18 + 20 = -79

  • Anonymous

    (g-f)(-9) is shortcut notation for g(-9) - f(-9): Just compute the two values and subtract: g(-9) = 2(-9) + 16 = -18 + 16 = -2 f(-9) = (-9)² - 4 = 81 - 4 = 77 Hence: g(-9) - f(-9) = -2 - 77 = -79

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