Anonymous

(-8)^2/3 Let cbrt = cube root cbrt{(-8)^2} cbrt{64} = 4 Answer: 4

Anonymous

= (- 8)^(2/3) → you know that: - 8 = (- 2) * (- 2) * (- 2) = - 2^(3) = [- 2^(3)]^(2/3) → you know that: [x^(a)]^(b) = x^(ab) = - 2^[3 * (2/3)] = - 2^(6/3) = - 2^(2) = - 2 * (- 2) = 4

Anonymous

(−8)^(2/3) = 64^(1/3) = 4

Anonymous

(−8)^(2/3) = ((−2)^(3))^(2/3) = (−2)^(3 * 2/3) {as (a^b)^c = a^(bc)} = (−2)^(2) = 4

Anonymous

This way =[(-8)^2]^(1/3) =[8^2]^(1/3) =[4^3]^(1/3) =4^[3*(1/3)] =4^1 =4

Anonymous

An exponent of ⅔ means the cube root of the square of the number. The square of -8 is 64. The cube root of 64 is 4. So, 4 is the answer. 4^3 = 4 * 4 * 4 = 64 This proves that 4 cubed is 64. So the cube root of 64 is 4. I hope this is helpful for you

Anonymous

As typed 64/3 If you mean (-8)^(2/3) (-2)^2 = 4

Anonymous

(-8^ ^ (2/3) = ((-8)^(1/3))^2 = (-2)^2 = 4 or.... (-8)^(2/3) = (-2^3)^(2/3) = -2^2 = 4

Anonymous

(-8)^1/3 is the cube root of -8. That would be -2, correct? and (-2)²=4. So your answer is 4.