Anonymous

Three capacitors of 2 F each in parallel achieve 6 Farad total capacity. (This is very high, so we would call this Super Capacitor)

Anonymous

3 possible combinations : # 3 i n series = F/3 = 2/3 F # 3 in parallel = 3F = 2*3 = 6 F # 2 in parallel iin series with the third = (2*2/(2+2))+2 = 3F

Anonymous

If three capacitors are 2/3 F each, then a total capacity of 2 F is easy to achieve.