You have questions? We got answers!

A boat travels 477 km in 9 hrs upstream and 515 km in 5 hrs downstream. rate of the boat in still water?and what is the rate of the current?

Science & Mathematics by Anonymous 2018-06-17 17:32:47

Social Science

A boat travels 477 km in 9 hrs upstream and 515 km in 5 hrs downstream. rate of the boat in still water?and what is the rate of the current?

4 answers

help!

  • Anonymous

    Ans. The rate of the boat=(515/5+477/9)/2=78 km/hr. The rate of the current=(515/5-477/9)/2=25 km/hr.

  • Anonymous

    A boat travels 477 km in 9 hrs upstream and 515 km in 5 hrs downstream. 53 = b - c 103 = b + c Rate of the boat in still water is 78 km per hour. and the rate of the current is 25 km per hour.

  • Anonymous

    v-c = 477/9 = 53 km/h v+c = 515/5 = 103 km/h v = boat speed in still water = 78 km/h c = current speed = 25 km/h

  • Anonymous

    Upstream: 477/9 = 53 kph Downstream 515/5 = 103 kph Rate in still water is the average speed for both journeys = (53 + 103)/2 = 78 kph Current = 78 - 53 = 25 kph or 103 - 78 = 25 kph

ReCapcha
Not a bot