Facebook
Google
You have questions? We got answers!
2 answers
The graph of the function f(x)=ax^2+bx+c has its vertex at (0,2) and passes through the point (1,3). Find A, B and C
-
Anonymous
f(x)=ax^2+bx+c f(0)=c=2 f(1)=a+b+2=3 => a+b=1-----(1) y '(x)=2ax+b => y'(0)=b=0 (since (0,2) is the vertex) => a=1 from (1) => f(x)=x^2+2 Ans. a=1, b=0 & c=2
-
Anonymous
f(x) = ax^2+bx+2 f'x) = 2ax+ b = 0 for turning points b = 0 3 = a+2 a = 1 f(x) = x^2+2 See graph https://www.desmos.com/calculator/hanyjg...
