Suppose a ball is thrown straight up into the air, and the height of the ball above the ground is given by the function? PLeaseee?

Science & Mathematics by Anonymous 2018-06-19 20:03:10

Social Science

5 answers

h(t) = 6 + 37t - 16t^2, where h is in feet and t is in seconds. What is the velocity of the ball at time t = 3.2? A. 53 ft/sec B. - 102.4 ft/sec C. 32.4 ft/sec D. - 65.4 ft/sec E. - 32.3 ft/sec

Anonymous

0 it's on the ground!
Anonymous

Is Timmy's calculator broken?
Anonymous

v = 37 - 3.2*32 = -65.4 ft/s Answer D However the ball hits the ground after 2.47 deconds!
Anonymous

h(t) = 6 + 37t - 16t^2 h'(t) = 37 - 32t h'(3.2) = 37 - 32(3.2)
Anonymous

The ball will have hit the ground before 3.2 seconds. Its height = 0. Its velocity = 0 as we have no information about whether it bounces, composition of the ball, surface on which it lands.