Anonymous

Let y = f(x) = -9 cos(10x + 6). Then -(1/9) y = cos(10x + 6) => 10x + 6 = arccos[-(1/9)y] => x = (1/10)*{arccos[-(1/9)y] - 6}, so the inverse function of f(x) is (1/10)*{arccos[-(1/9)x] - 6}.

Anonymous

Ans. y=[cos^-1(-x/9)-6]/10. Note that it is not a function.

Anonymous

y = -9 cos (10x + 6) x = -9 cos (10y + 6) cos (10y + 6) = -x/9 10y + 6 = Arccos (-x/9) 10y = Arccos (-x/9) - 6 y = [Arccos (-x/9) - 6] / 10 f^-1(x) = [Arccos (-x/9) - 6] / 10

Anonymous

since f is NOT 1 to 1 no inverse exists....read the definition of an inverse function !!