Need help with this please write out a correct rearrangement of the formula 2a = b – c ( b/3

Science & Mathematics by Anonymous 2018-05-11 11:08:59

Social Science

Need help with this please write out a correct rearrangement of the formula 2a = b – c ( b/3 – 4) making b the subject?

4 answers

Anonymous
Anonymous

2a = b - bc/3 + 4c b - bc/3 = 4c - 2a b(1 - c/3) = 4c - 2a b = 2(2c - a) / (1 - c/3)
Anonymous

2a = b – c ( b/3 – 4) 2a = b - bc/3 + 4c 2a - 4c = b(1-c/3) b(3-c)/3 = 2(a-2c) ans: b = 6(a-2c)/(3-c) : c ≠ 3
Anonymous

2a = b – c ( b/3 – 4) b = 2a + c ( b/3 – 4) b – bc/3 = 2a – 4c b(1 – c/3) = 2(a – 2c) -1/3 b (c - 3) = 2 (a - 2 c) - b (c - 3) = 6(a - 2c) b (3 - c) = 6 (a - 2c) b = 6 (a - 2c) / (3 - c)