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Find two numbers such that the sum of the first and 3 times the second is 33, while 8 times the second exceeds 3 times the first by 20.?

Science & Mathematics by Anonymous 2018-06-24 02:33:28

Social Science

Find two numbers such that the sum of the first and 3 times the second is 33, while 8 times the second exceeds 3 times the first by 20.?

5 answers

  • Anonymous

    3b + a = 33, so, 9b + 3a = 99 8b - 3a = 20 b = 119/17 = 7 a = 33 – 21 = 12

  • Anonymous

    x + 3y = 33 8y = 3x + 20 3x + 9y = 99 - 3x + 8y = 20_______add 17y = 119 y = 7 x + 21 = 33 x = 12 Numbers are 7 and 12

  • Anonymous

    x +3y = 33 x = 33 -3y 8y -3x = 20 8y -3(33 -3y) = 20 17y = 119 y = 7 x = 12

  • Anonymous

    Yes, I think so

  • Anonymous

    go ahead and find those numbers, boy

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