Find values for A, B, C if y^2 +16y + 94 - 6x is expressed in the form (y + C)^2

Science & Mathematics by Anonymous 2018-06-24 11:01:59

Social Science

Find values for A, B, C if y^2 +16y + 94 - 6x is expressed in the form (y + C)^2 - B(x + A)?

4 answers

Anonymous

(y+C)² - B(x+A) = y² + 2Cy + C² - Bx - AB y² + 2Cy + C² - Bx - AB = y² + 16y + 94 - 6x 2Cy + (C²-AB) - Bx = 16y + 94 - 6x C = 8 B = 6 C² - AB = 94 64 - 6A = 94 A = -5
Anonymous

y^2 +16y + 94 - 6x =y²+2*8*y+8²+30 -6x =(y+8)²-6(x-5) =(y + C)^2 - B(x + A) Hence C=8 B=6 and A=-5
Anonymous

y^2 + 16y + 94 - 6x = y^2 + 16y + (16/8)^2 - 6x + 94 - (16/8)^2 = (y + 8)^2 - 6x + 30 = (y + 8)^2 - 6(x - 5) A = -5, B = 6, C = 8
Anonymous

(y + c)^2 - b * (x + a) => y^2 + 2cy + c^2 - bx - ba => y^2 + 2cy - bx + c^2 - ba y^2 = y^2 2cy = 16y -bx = -6x c^2 - ba = 94 2c = 16 c = 8 -b = -6 b = 6 8^2 - 6 * a = 94 64 - 6a = 94 -30 = 6a a = -5