Help with pythagorean theorem world problem?

Science & Mathematics by Anonymous 2018-06-26 15:33:13

Social Science

2 answers

Determine the length of an inclined plane whose measure is 10 meters longer than the rise and the run is 8 meters longer than the rise.

Anonymous

The plane (hypotenuse) is 10 meters longer than the rise, and is also 10 - 8= 2 meters longer than the run. So the plane is 10 + 2 + √(2*10*2) = 12 + 2√10 ≈ 18.3 meters.
Anonymous

We have L = R + 10 and N = R + 8; so L^2 = (R^2 + 20R + 100) = R^2 + (R^2 + 16R + 64) = R^2 + N^2 from the Pythagorean equation. From which we find the quad R^2 -4R - 36 = 0 which has the solution R = 8.33 so that L = 18.33 m ANS.