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Find S8 for the geometric series 3 + -6 + 12 + -24 +…?

Science & Mathematics by Anonymous 2018-06-27 04:33:53

Social Science

Find S8 for the geometric series 3 + -6 + 12 + -24 +…?

6 answers

  • Anonymous

    3 + -6 + 12 + -24 +… Here first term, a =3 and common ratio, r = -6/3=-2 hence S8 =a(r^8 -1)/(r-1)= 3{(-2)^8 -1}/{(-2-1) = 3{256-1)(-3) = -255

  • Anonymous

    a = 3, r = -6/3 = -2 |r| = |-2| = 2 > 0 Sn = a(r^n - 1)/(r - 1) S_8 = 3((-2)^8 - 1)/(-2 - 1) = -255

  • Anonymous

    S(8) = (3 + -6) + (12 + -24) + 16((3 + -6) + (12 + -24) ) S(8) = -3 + -12 + -48 + -192 S(8) = -255

  • Anonymous

    For the geometric series 3 + (-6) + 12 + (-24) + …… The first term, a = 3 The common factor, r = -2 S(8) = a (1 - r⁸) / (1 - r) = 3 [1 - (-2)⁸] / [1 - (-2)] = 3 × (-255) / 3 = -255

  • Anonymous

    3, - 6, 12, -24, ... an = -3 (-1)^n 2^(n - 1) 3 - 6 + 12 - 24 + 48 - 96 + 192 - 384 = 255 - 510 = -255

  • Anonymous

    S_n = ( a_1 ) [ 1 - r^(n+1) ] / [ 1 - r ]

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