Anonymous

(-1,-2) -> (r = sqrt(5),theta = (arctan(2) + pi)*2*pi*n); where n is the element of the integer values

Anonymous

We have (x,y) --> (-1,-2) --> -1 = R cos(theta) and - 2 = R sin(theta); so 2 = tan(theta) and theta = ATAN(2) = 63.4 deg but into quadrant III. So - 116.6 deg. And the R = -2/sin(radians(243.4)) = 2.24. Which gives the polar: (2.24,-2.03) ANS.

Anonymous

tan(θ) = y/x There are two angles with the same tangent, so make sure you pick the one in the correct quadrant.

Anonymous

You have to start with a polar bear...