Anonymous

This circle has a radius of 2 (the centre being two units to the left of the y axis to which it is tangent) We start with (x+2)² + (y+3)² = 2² and expand and simplify x² + 4x + 4 + y² + 6y + 9 = 4 x² + y² + 4x + 6y + 9 = 0

Anonymous

r = 3 [ x + 2 ]^2 + [ y + 3 ]^2 = 4 x^2 + 4x + 4 + y^2 + 6y + 9 = 4 x^2 + y^2 + 4x + 6y + 9 = 0