Trying to slove this math problem.. its hard y^(2)-xy+x^(2)=5 differentiate implicitly to find (dy)/(dx)?

Science & Mathematics by Anonymous 2018-07-02 02:03:33

Social Science

6 answers

Anonymous

2y dy/dx - [ y + x dy/dx ] + 2x = 0 [ 2y - x ] dy/dx = y - 2x dy/dx = [ y - 2x ] / [ 2y - x ]
Anonymous

y^2 - xy + x^2 = 5 2y(dy/dx) - (x(dy/dx) + y) + 2x = 0 (dy/dx)(2y - x) = y - 2x dy/dx = (2y - x)/(y - 2x)
Anonymous

Write it as f(x,y) = y² - xy +x²-5=0 Differentiate it df= df/dx dx +df/dy dy. Here df/dx and df/dy are partial derivatives df= (-y +2x) dx + (2y -x) dy=0 This gives dy/dx= (y-2x)/(2x-y) This will be the answer.
Anonymous

2yy'-[y+xy']+2x = 0 2yy'-y-xy'+2x = 0 y'(2y-x) = y-2x dy/dx = (y-2x)/(2y-x)
Anonymous

(dy)/(dx) = y' 2yy'-xy' - y + 2x=0 --->y' = ...
Anonymous

dy/dx = -(2x+y)/(x+2y)