Anonymous

4x^2 − 4x + 1 = 4(x^2 − x + 1/4) = (1 - 2x)^2 = (2x - 1)^2 4x^2 − 4x + 1 = 0 (2x − 1)^2 = 0

Anonymous

4x² − 4x + 1 = 0 4(x² - x) + 1 = 0 4(x² - x + (-1/2)² - (-1/2)²) + 1 = 0 4(x - 1/2)² -4/4 + 1 = 0 4(x - 1/2)² = 0 (x - 1/2)² = 0

Anonymous

4x^2−4x+1=0. Write it as 4x^2 +4x +1= 8x (2x+1)²= 8x (x+1/2)²= 2x. This is ghe answer

Anonymous

4x^2−4x+1=0 (2x)² −2*2x*1+1²=0 i.e. (2x−1)²=0 or 2²{x+(−1/4)}²=0 or {x+(−1/4)}²=0

Anonymous

4x² - 4x + 1 = 0 x² - x + (1/4) = 0 x² - x = - (1/4) x² - x + (1/2)² = - (1/4) + (1/2)² x² - x + (1/2)² = - (1/4) + (1/4) [x - (1/2)]² = 0 → to go further x - (1/2) = 0 x = 1/2

Anonymous

4[x^2-x]=-1 4[x^2-x+1/4] = -1+1 4(x-1/2)^2 = 0 (x-1/2)^2 = 0

Anonymous

4x^2 - 4x + 1 = 0 (2x - 1)^2 = 0 x = 1/2